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Configuration = 45
cycles = (10 5 1 8 2)(9 6 3 7 4)

a = 5, b = 8, c = 10
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cycles = (10 2)(9 4 6 8 3)(7)(5 1)

a = 4, b = 6, c = 9
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cycles = (10 2)(9 6 3)(8 1)(7)(5)(4)

a = 2, b = 8, c = 10
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cycles = (10 1 2)(9)(8 5 3)(7)(6)(4)

a = 1, b = 2, c = 10
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cycles = (10)(9)(8)(7 4 2)(6)(5)(3)(1)